Rebar modeling in two dimensions

You can define rebar in two-dimensional elements.

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Defining rebar as an element property

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Let gi,    i=1, 2 be the element's usual isoparametric coordinates. Let r be an isoparametric coordinate along the line where the face of the element intersects the plane of reinforcement, with -1≤r≤1 in an element (see Figure 1).

Figure 1. Rebar in a solid, two-dimensional element.

The plane of reinforcement is always perpendicular to the element face.

The rebar will be integrated at one or two points, depending on the order of interpolation in underlying elements. The volume of integration (Δ⁢V), position, rebar strain (ε), and first and second variations of rebar strain (δε and dδε) at each point are calculated as

Δ⁢V=ArSr⁢(∂⁡x∂⁡r⋅∂⁡x∂⁡r)12⁢t0    WN,

where

t0

is the original thickness for plane elements and 2⁢π⁢x1 for axisymmetric elements;

Ar

is the rebar cross-sectional area;

Sr

is the spacing of rebar (for axisymmetric elements Sr=(x1/x10)⁢Sr0, where x10 is the radius where the spacing Sr0 is given);

WN

is the Gauss weight associated with the integration point along the (r) line;

x=x⁢(gi)

is position; and

∂⁡x∂⁡r=∂⁡x∂⁡gi⁢∂⁡gi∂⁡r.

Strain is

ε=12⁢ln⁡(d⁢l2d⁢lo2),

where d⁢l and d⁢lo measure length along the rebar in the current and initial configurations, respectively.

For the deformations allowed in these elements,

(d⁢ld⁢lo)2=cos2⁡α⁢λr2+sin2⁡α⁢λt2,

where α is the orientation of the rebar from the plane of the model,

λr2=∂⁡x∂⁡r⋅∂⁡x∂⁡r/∂⁡xo∂⁡r⋅∂⁡xo∂⁡r

is the squared stretch ratio in the r-direction, and λt is the stretch ratio in the thickness direction:

λt=1

for plane stress or plane strain;

λt=t/to

for generalized plane strain, where t is given in Generalized plane strain elements; and

λt=x1/x1o

for axisymmetric elements.

From these results the first variation of strain is

δε=(d⁢lod⁢l)2    (cos2α∂⁡x∂⁡r⋅∂⁡δ⁢x∂⁡r/∂⁡xo∂⁡r⋅∂⁡xo∂⁡r+δpt),

where

δ⁢pt=0

for plane stress and plane strain,

δ⁢pt=sin2⁡α⁢t⁢δ⁢t/to2

for generalized plane strain, and

δ⁢pt=sin2⁡α⁢x1⁢δ⁢x1/x1o2

for axisymmetric cases.

The second variation of strain is then

d⁢δ⁢ε=-2⁢(d⁢lod⁢l)2⁢(cos2⁡α⁢∂⁡x∂⁡r⋅∂⁡δ⁢x∂⁡r/∂⁡xo∂⁡r⋅∂⁡xo∂⁡r+δ⁢pt)⋅(cos2⁡α⁢∂⁡x∂⁡r⋅∂⁡d⁢x∂⁡r/∂⁡xo∂⁡r⋅∂⁡xo∂⁡r+d⁢pt)+(d⁢lod⁢l)2⁢(cos2⁡α⁢∂⁡d⁢x∂⁡r⋅∂⁡δ⁢x∂⁡r/∂⁡xo∂⁡r⋅∂⁡xo∂⁡r+d⁢δ⁢pt).